[[["이해하기 쉬움","easyToUnderstand","thumb-up"],["문제가 해결됨","solvedMyProblem","thumb-up"],["기타","otherUp","thumb-up"]],[["필요한 정보가 없음","missingTheInformationINeed","thumb-down"],["너무 복잡함/단계 수가 너무 많음","tooComplicatedTooManySteps","thumb-down"],["오래됨","outOfDate","thumb-down"],["번역 문제","translationIssue","thumb-down"],["샘플/코드 문제","samplesCodeIssue","thumb-down"],["기타","otherDown","thumb-down"]],["최종 업데이트: 2025-07-26(UTC)"],[[["Calculates the circular standard deviation of input values, assuming they are in radians."],["Employs the `sqrt(-2 * ln(R))` formula for computation."],["Outputs are typically named \"circularStdDev\"."],["Available through the `ee.Reducer.circularStddev()` function, which returns a Reducer."],["Does not require any arguments for usage."]]],["This function creates a Reducer that calculates the circular standard deviation of input values, assumed to be in radians. It uses the formula sqrt(-2 \\* ln(R)). The output of the reducer, when applicable, is named \"circularStdDev\". It does not accept any arguments and returns a Reducer object. The main action is computing this circular standard deviation.\n"]]
