[[["易于理解","easyToUnderstand","thumb-up"],["解决了我的问题","solvedMyProblem","thumb-up"],["其他","otherUp","thumb-up"]],[["没有我需要的信息","missingTheInformationINeed","thumb-down"],["太复杂/步骤太多","tooComplicatedTooManySteps","thumb-down"],["内容需要更新","outOfDate","thumb-down"],["翻译问题","translationIssue","thumb-down"],["示例/代码问题","samplesCodeIssue","thumb-down"],["其他","otherDown","thumb-down"]],["最后更新时间 (UTC):2025-07-26。"],[],["The `lte` function compares two numbers and returns a numerical result. It assesses if the left-hand value (`this`) is less than or equal to the right-hand value (`right`). It returns `1` if this condition is true and `0` if it is false. The function's usage is `Number.lte(right)`. Both input values must be numbers. For instance, 5 `lte` 10 returns 1, while 10 `lte` 5 returns 0.\n"]]