این بخش نحوه حل مشکل کوله پشتی برای چند کوله پشتی را با استفاده از حل کننده MIP و حل کننده CP-SAT نشان می دهد. در این مورد، رایج است که به ظروف به جای کوله پشتی به عنوان سطل زباله اطلاق می شود.
مثال بعدی نحوه یافتن راه بهینه برای بسته بندی اقلام در پنج سطل را نشان می دهد.
مثال
مانند مثال قبلی ، شما با مجموعه ای از آیتم ها با وزن ها و مقادیر متفاوت شروع می کنید. مشکل این است که یک زیرمجموعه از اقلام را در پنج سطل بسته بندی کنیم که هر کدام حداکثر ظرفیت 100 را دارند، به طوری که مقدار کل بسته بندی شده حداکثر باشد.
بخش‌های زیر بخش‌هایی از برنامه‌هایی را ارائه می‌کنند که این مشکل را حل می‌کنند. برای برنامه های کامل، برنامه های کامل را ببینید.
راه حل MIP
بخش‌های زیر نحوه حل مشکل با استفاده از پوشش MPSolver را شرح می‌دهند.
کتابخانه ها را وارد کنید
کد زیر کتابخانه های مورد نیاز را وارد می کند.
پایتون
from ortools.linear_solver import pywraplp
C++
#include <iostream> #include <memory> #include <numeric> #include <vector> #include "absl/strings/str_format.h" #include "ortools/linear_solver/linear_expr.h" #include "ortools/linear_solver/linear_solver.h"
جاوا
import com.google.ortools.Loader; import com.google.ortools.linearsolver.MPConstraint; import com.google.ortools.linearsolver.MPObjective; import com.google.ortools.linearsolver.MPSolver; import com.google.ortools.linearsolver.MPVariable; import java.util.stream.IntStream;
سی شارپ
using System; using System.Collections.Generic; using System.Linq; using Google.OrTools.LinearSolver;
داده ها را ایجاد کنید
کد زیر داده های مشکل را ایجاد می کند.
پایتون
data = {}
data["weights"] = [48, 30, 42, 36, 36, 48, 42, 42, 36, 24, 30, 30, 42, 36, 36]
data["values"] = [10, 30, 25, 50, 35, 30, 15, 40, 30, 35, 45, 10, 20, 30, 25]
assert len(data["weights"]) == len(data["values"])
data["num_items"] = len(data["weights"])
data["all_items"] = range(data["num_items"])
data["bin_capacities"] = [100, 100, 100, 100, 100]
data["num_bins"] = len(data["bin_capacities"])
data["all_bins"] = range(data["num_bins"])C++
const std::vector<int> weights = {
{48, 30, 42, 36, 36, 48, 42, 42, 36, 24, 30, 30, 42, 36, 36}};
const std::vector<int> values = {
{10, 30, 25, 50, 35, 30, 15, 40, 30, 35, 45, 10, 20, 30, 25}};
const int num_items = weights.size();
std::vector<int> all_items(num_items);
std::iota(all_items.begin(), all_items.end(), 0);
const std::vector<int> bin_capacities = {{100, 100, 100, 100, 100}};
const int num_bins = bin_capacities.size();
std::vector<int> all_bins(num_bins);
std::iota(all_bins.begin(), all_bins.end(), 0);جاوا
final double[] weights = {48, 30, 42, 36, 36, 48, 42, 42, 36, 24, 30, 30, 42, 36, 36};
final double[] values = {10, 30, 25, 50, 35, 30, 15, 40, 30, 35, 45, 10, 20, 30, 25};
final int numItems = weights.length;
final int[] allItems = IntStream.range(0, numItems).toArray();
final double[] binCapacities = {100, 100, 100, 100, 100};
final int numBins = binCapacities.length;
final int[] allBins = IntStream.range(0, numBins).toArray();سی شارپ
double[] Weights = { 48, 30, 42, 36, 36, 48, 42, 42, 36, 24, 30, 30, 42, 36, 36 };
double[] Values = { 10, 30, 25, 50, 35, 30, 15, 40, 30, 35, 45, 10, 20, 30, 25 };
int NumItems = Weights.Length;
int[] allItems = Enumerable.Range(0, NumItems).ToArray();
double[] BinCapacities = { 100, 100, 100, 100, 100 };
int NumBins = BinCapacities.Length;
int[] allBins = Enumerable.Range(0, NumBins).ToArray();داده ها شامل موارد زیر است:
-
weights: بردار حاوی وزن آیتم ها. -
values: بردار حاوی مقادیر آیتم ها. -
capacities: بردار حاوی ظرفیت های سطل ها.
در این مثال، همه سطل ها ظرفیت یکسانی دارند، اما به طور کلی نیازی به این نیست که درست باشد.
حل کننده MIP را اعلام کنید
کد زیر حل کننده MIP را اعلام می کند.
پایتون
solver = pywraplp.Solver.CreateSolver("SCIP")
if solver is None:
print("SCIP solver unavailable.")
returnC++
std::unique_ptr<MPSolver> solver(MPSolver::CreateSolver("SCIP"));
if (!solver) {
LOG(WARNING) << "SCIP solver unavailable.";
return;
}جاوا
// Create the linear solver with the SCIP backend.
MPSolver solver = MPSolver.createSolver("SCIP");
if (solver == null) {
System.out.println("Could not create solver SCIP");
return;
}سی شارپ
// Create the linear solver with the SCIP backend.
Solver solver = Solver.CreateSolver("SCIP");
if (solver is null)
{
return;
}متغیرها را ایجاد کنید
کد زیر متغیرهای مشکل را ایجاد می کند.
پایتون
# x[i, b] = 1 if item i is packed in bin b.
x = {}
for i in data["all_items"]:
for b in data["all_bins"]:
x[i, b] = solver.BoolVar(f"x_{i}_{b}")C++
// x[i][b] = 1 if item i is packed in bin b.
std::vector<std::vector<const MPVariable*>> x(
num_items, std::vector<const MPVariable*>(num_bins));
for (int i : all_items) {
for (int b : all_bins) {
x[i][b] = solver->MakeBoolVar(absl::StrFormat("x_%d_%d", i, b));
}
}جاوا
MPVariable[][] x = new MPVariable[numItems][numBins];
for (int i : allItems) {
for (int b : allBins) {
x[i][b] = solver.makeBoolVar("x_" + i + "_" + b);
}
}سی شارپ
Variable[,] x = new Variable[NumItems, NumBins];
foreach (int i in allItems)
{
foreach (int b in allBins)
{
x[i, b] = solver.MakeBoolVar($"x_{i}_{b}");
}
} هر x[(i, j)] یک متغیر 0-1 است که i یک آیتم و j یک bin است. در راه حل، اگر مورد i در bin j قرار گیرد x[(i, j)] 1 خواهد بود و در غیر این صورت 0 خواهد بود.
محدودیت ها را تعریف کنید
کد زیر محدودیت های مشکل را تعریف می کند:
پایتون
# Each item is assigned to at most one bin.
for i in data["all_items"]:
solver.Add(sum(x[i, b] for b in data["all_bins"]) <= 1)
# The amount packed in each bin cannot exceed its capacity.
for b in data["all_bins"]:
solver.Add(
sum(x[i, b] * data["weights"][i] for i in data["all_items"])
<= data["bin_capacities"][b]
)C++
// Each item is assigned to at most one bin.
for (int i : all_items) {
LinearExpr sum;
for (int b : all_bins) {
sum += x[i][b];
}
solver->MakeRowConstraint(sum <= 1.0);
}
// The amount packed in each bin cannot exceed its capacity.
for (int b : all_bins) {
LinearExpr bin_weight;
for (int i : all_items) {
bin_weight += LinearExpr(x[i][b]) * weights[i];
}
solver->MakeRowConstraint(bin_weight <= bin_capacities[b]);
}جاوا
// Each item is assigned to at most one bin.
for (int i : allItems) {
MPConstraint constraint = solver.makeConstraint(0, 1, "");
for (int b : allBins) {
constraint.setCoefficient(x[i][b], 1);
}
}
// The amount packed in each bin cannot exceed its capacity.
for (int b : allBins) {
MPConstraint constraint = solver.makeConstraint(0, binCapacities[b], "");
for (int i : allItems) {
constraint.setCoefficient(x[i][b], weights[i]);
}
}سی شارپ
// Each item is assigned to at most one bin.
foreach (int i in allItems)
{
Constraint constraint = solver.MakeConstraint(0, 1, "");
foreach (int b in allBins)
{
constraint.SetCoefficient(x[i, b], 1);
}
}
// The amount packed in each bin cannot exceed its capacity.
foreach (int b in allBins)
{
Constraint constraint = solver.MakeConstraint(0, BinCapacities[b], "");
foreach (int i in allItems)
{
constraint.SetCoefficient(x[i, b], Weights[i]);
}
}محدودیت ها به شرح زیر است:
- هر مورد را می توان حداکثر در یک سطل قرار داد. این محدودیت با الزام مجموع
x[i, j]در تمام bin هایjبه کمتر یا مساوی 1 تنظیم می شود. - وزن کل بسته بندی شده در هر سطل نمی تواند از ظرفیت آن بیشتر باشد. این محدودیت با الزام مجموع وزن اقلام قرار داده شده در bin
jبه کمتر یا مساوی ظرفیت سطل تنظیم می شود.
هدف را تعریف کنید
کد زیر تابع هدف را برای مشکل تعریف می کند که مقدار کل آیتم های بسته بندی شده است.
پایتون
# Maximize total value of packed items.
objective = solver.Objective()
for i in data["all_items"]:
for b in data["all_bins"]:
objective.SetCoefficient(x[i, b], data["values"][i])
objective.SetMaximization()C++
// Maximize total value of packed items.
MPObjective* const objective = solver->MutableObjective();
LinearExpr objective_value;
for (int i : all_items) {
for (int b : all_bins) {
objective_value += LinearExpr(x[i][b]) * values[i];
}
}
objective->MaximizeLinearExpr(objective_value);جاوا
// Maximize total value of packed items.
MPObjective objective = solver.objective();
for (int i : allItems) {
for (int b : allBins) {
objective.setCoefficient(x[i][b], values[i]);
}
}
objective.setMaximization();سی شارپ
Objective objective = solver.Objective();
foreach (int i in allItems)
{
foreach (int b in allBins)
{
objective.SetCoefficient(x[i, b], Values[i]);
}
}
objective.SetMaximization(); توجه داشته باشید که x[i, j] * data['values'][i] اگر آیتم در bin j قرار گیرد، مقدار i را به هدف اضافه می کند. اگر i در هیچ bin قرار نگیرد، مقدار آن به هدف کمک نمی کند.
حل کننده را فراخوانی کنید
کد زیر حل کننده را فراخوانی می کند.
پایتون
print(f"Solving with {solver.SolverVersion()}")
status = solver.Solve()C++
const MPSolver::ResultStatus result_status = solver->Solve();
جاوا
final MPSolver.ResultStatus status = solver.solve();
سی شارپ
Solver.ResultStatus resultStatus = solver.Solve();
محلول را چاپ کنید
کد زیر راه حل مشکل را چاپ می کند.
پایتون
if status == pywraplp.Solver.OPTIMAL:
print(f"Total packed value: {objective.Value()}")
total_weight = 0
for b in data["all_bins"]:
print(f"Bin {b}")
bin_weight = 0
bin_value = 0
for i in data["all_items"]:
if x[i, b].solution_value() > 0:
print(
f"Item {i} weight: {data['weights'][i]} value:"
f" {data['values'][i]}"
)
bin_weight += data["weights"][i]
bin_value += data["values"][i]
print(f"Packed bin weight: {bin_weight}")
print(f"Packed bin value: {bin_value}\n")
total_weight += bin_weight
print(f"Total packed weight: {total_weight}")
else:
print("The problem does not have an optimal solution.")C++
if (result_status == MPSolver::OPTIMAL) {
LOG(INFO) << "Total packed value: " << objective->Value();
double total_weight = 0.0;
for (int b : all_bins) {
LOG(INFO) << "Bin " << b;
double bin_weight = 0.0;
double bin_value = 0.0;
for (int i : all_items) {
if (x[i][b]->solution_value() > 0) {
LOG(INFO) << "Item " << i << " weight: " << weights[i]
<< " value: " << values[i];
bin_weight += weights[i];
bin_value += values[i];
}
}
LOG(INFO) << "Packed bin weight: " << bin_weight;
LOG(INFO) << "Packed bin value: " << bin_value;
total_weight += bin_weight;
}
LOG(INFO) << "Total packed weight: " << total_weight;
} else {
LOG(INFO) << "The problem does not have an optimal solution.";
}جاوا
// Check that the problem has an optimal solution.
if (status == MPSolver.ResultStatus.OPTIMAL) {
System.out.println("Total packed value: " + objective.value());
double totalWeight = 0;
for (int b : allBins) {
double binWeight = 0;
double binValue = 0;
System.out.println("Bin " + b);
for (int i : allItems) {
if (x[i][b].solutionValue() == 1) {
System.out.println("Item " + i + " weight: " + weights[i] + " value: " + values[i]);
binWeight += weights[i];
binValue += values[i];
}
}
System.out.println("Packed bin weight: " + binWeight);
System.out.println("Packed bin value: " + binValue);
totalWeight += binWeight;
}
System.out.println("Total packed weight: " + totalWeight);
} else {
System.err.println("The problem does not have an optimal solution.");
}سی شارپ
// Check that the problem has an optimal solution.
if (resultStatus == Solver.ResultStatus.OPTIMAL)
{
Console.WriteLine($"Total packed value: {solver.Objective().Value()}");
double TotalWeight = 0.0;
foreach (int b in allBins)
{
double BinWeight = 0.0;
double BinValue = 0.0;
Console.WriteLine("Bin " + b);
foreach (int i in allItems)
{
if (x[i, b].SolutionValue() == 1)
{
Console.WriteLine($"Item {i} weight: {Weights[i]} values: {Values[i]}");
BinWeight += Weights[i];
BinValue += Values[i];
}
}
Console.WriteLine("Packed bin weight: " + BinWeight);
Console.WriteLine("Packed bin value: " + BinValue);
TotalWeight += BinWeight;
}
Console.WriteLine("Total packed weight: " + TotalWeight);
}
else
{
Console.WriteLine("The problem does not have an optimal solution!");
}برای هر سطل، کد اقلام قرار داده شده در آن سطل، و همچنین ارزش و وزن کل سطل را نمایش می دهد. این کد همچنین ارزش کلی و وزن اقلام بسته بندی شده را نشان می دهد.
وقتی برنامه را اجرا می کنید، خروجی زیر را نمایش می دهد.
Total packed value: 395.0 Bin 0 Item 3 - weight: 36 value: 50 Item 13 - weight: 36 value: 30 Packed bin weight: 72 Packed bin value: 80 Bin 1 Item 5 - weight: 48 value: 30 Item 7 - weight: 42 value: 40 Packed bin weight: 90 Packed bin value: 70 Bin 2 Item 1 - weight: 30 value: 30 Item 10 - weight: 30 value: 45 Item 14 - weight: 36 value: 25 Packed bin weight: 96 Packed bin value: 100 Bin 3 Item 2 - weight: 42 value: 25 Item 12 - weight: 42 value: 20 Packed bin weight: 84 Packed bin value: 45 Bin 4 Item 4 - weight: 36 value: 35 Item 8 - weight: 36 value: 30 Item 9 - weight: 24 value: 35 Packed bin weight: 96 Packed bin value: 100 Total packed weight: 438
برنامه های کامل
برنامه های کامل برای چند کوله پشتی در زیر نشان داده شده است.
پایتون
"""Solve a multiple knapsack problem using a MIP solver."""
from ortools.linear_solver import pywraplp
def main():
data = {}
data["weights"] = [48, 30, 42, 36, 36, 48, 42, 42, 36, 24, 30, 30, 42, 36, 36]
data["values"] = [10, 30, 25, 50, 35, 30, 15, 40, 30, 35, 45, 10, 20, 30, 25]
assert len(data["weights"]) == len(data["values"])
data["num_items"] = len(data["weights"])
data["all_items"] = range(data["num_items"])
data["bin_capacities"] = [100, 100, 100, 100, 100]
data["num_bins"] = len(data["bin_capacities"])
data["all_bins"] = range(data["num_bins"])
# Create the mip solver with the SCIP backend.
solver = pywraplp.Solver.CreateSolver("SCIP")
if solver is None:
print("SCIP solver unavailable.")
return
# Variables.
# x[i, b] = 1 if item i is packed in bin b.
x = {}
for i in data["all_items"]:
for b in data["all_bins"]:
x[i, b] = solver.BoolVar(f"x_{i}_{b}")
# Constraints.
# Each item is assigned to at most one bin.
for i in data["all_items"]:
solver.Add(sum(x[i, b] for b in data["all_bins"]) <= 1)
# The amount packed in each bin cannot exceed its capacity.
for b in data["all_bins"]:
solver.Add(
sum(x[i, b] * data["weights"][i] for i in data["all_items"])
<= data["bin_capacities"][b]
)
# Objective.
# Maximize total value of packed items.
objective = solver.Objective()
for i in data["all_items"]:
for b in data["all_bins"]:
objective.SetCoefficient(x[i, b], data["values"][i])
objective.SetMaximization()
print(f"Solving with {solver.SolverVersion()}")
status = solver.Solve()
if status == pywraplp.Solver.OPTIMAL:
print(f"Total packed value: {objective.Value()}")
total_weight = 0
for b in data["all_bins"]:
print(f"Bin {b}")
bin_weight = 0
bin_value = 0
for i in data["all_items"]:
if x[i, b].solution_value() > 0:
print(
f"Item {i} weight: {data['weights'][i]} value:"
f" {data['values'][i]}"
)
bin_weight += data["weights"][i]
bin_value += data["values"][i]
print(f"Packed bin weight: {bin_weight}")
print(f"Packed bin value: {bin_value}\n")
total_weight += bin_weight
print(f"Total packed weight: {total_weight}")
else:
print("The problem does not have an optimal solution.")
if __name__ == "__main__":
main()C++
// Solve a multiple knapsack problem using a MIP solver.
#include <iostream>
#include <memory>
#include <numeric>
#include <vector>
#include "absl/strings/str_format.h"
#include "ortools/linear_solver/linear_expr.h"
#include "ortools/linear_solver/linear_solver.h"
namespace operations_research {
void MultipleKnapsackMip() {
const std::vector<int> weights = {
{48, 30, 42, 36, 36, 48, 42, 42, 36, 24, 30, 30, 42, 36, 36}};
const std::vector<int> values = {
{10, 30, 25, 50, 35, 30, 15, 40, 30, 35, 45, 10, 20, 30, 25}};
const int num_items = weights.size();
std::vector<int> all_items(num_items);
std::iota(all_items.begin(), all_items.end(), 0);
const std::vector<int> bin_capacities = {{100, 100, 100, 100, 100}};
const int num_bins = bin_capacities.size();
std::vector<int> all_bins(num_bins);
std::iota(all_bins.begin(), all_bins.end(), 0);
// Create the mip solver with the SCIP backend.
std::unique_ptr<MPSolver> solver(MPSolver::CreateSolver("SCIP"));
if (!solver) {
LOG(WARNING) << "SCIP solver unavailable.";
return;
}
// Variables.
// x[i][b] = 1 if item i is packed in bin b.
std::vector<std::vector<const MPVariable*>> x(
num_items, std::vector<const MPVariable*>(num_bins));
for (int i : all_items) {
for (int b : all_bins) {
x[i][b] = solver->MakeBoolVar(absl::StrFormat("x_%d_%d", i, b));
}
}
// Constraints.
// Each item is assigned to at most one bin.
for (int i : all_items) {
LinearExpr sum;
for (int b : all_bins) {
sum += x[i][b];
}
solver->MakeRowConstraint(sum <= 1.0);
}
// The amount packed in each bin cannot exceed its capacity.
for (int b : all_bins) {
LinearExpr bin_weight;
for (int i : all_items) {
bin_weight += LinearExpr(x[i][b]) * weights[i];
}
solver->MakeRowConstraint(bin_weight <= bin_capacities[b]);
}
// Objective.
// Maximize total value of packed items.
MPObjective* const objective = solver->MutableObjective();
LinearExpr objective_value;
for (int i : all_items) {
for (int b : all_bins) {
objective_value += LinearExpr(x[i][b]) * values[i];
}
}
objective->MaximizeLinearExpr(objective_value);
const MPSolver::ResultStatus result_status = solver->Solve();
if (result_status == MPSolver::OPTIMAL) {
LOG(INFO) << "Total packed value: " << objective->Value();
double total_weight = 0.0;
for (int b : all_bins) {
LOG(INFO) << "Bin " << b;
double bin_weight = 0.0;
double bin_value = 0.0;
for (int i : all_items) {
if (x[i][b]->solution_value() > 0) {
LOG(INFO) << "Item " << i << " weight: " << weights[i]
<< " value: " << values[i];
bin_weight += weights[i];
bin_value += values[i];
}
}
LOG(INFO) << "Packed bin weight: " << bin_weight;
LOG(INFO) << "Packed bin value: " << bin_value;
total_weight += bin_weight;
}
LOG(INFO) << "Total packed weight: " << total_weight;
} else {
LOG(INFO) << "The problem does not have an optimal solution.";
}
}
} // namespace operations_research
int main(int argc, char** argv) {
operations_research::MultipleKnapsackMip();
return EXIT_SUCCESS;
}جاوا
// Solve a multiple knapsack problem using a MIP solver.
package com.google.ortools.linearsolver.samples;
import com.google.ortools.Loader;
import com.google.ortools.linearsolver.MPConstraint;
import com.google.ortools.linearsolver.MPObjective;
import com.google.ortools.linearsolver.MPSolver;
import com.google.ortools.linearsolver.MPVariable;
import java.util.stream.IntStream;
/** Multiple knapsack problem. */
public class MultipleKnapsackMip {
public static void main(String[] args) {
Loader.loadNativeLibraries();
// Instantiate the data problem.
final double[] weights = {48, 30, 42, 36, 36, 48, 42, 42, 36, 24, 30, 30, 42, 36, 36};
final double[] values = {10, 30, 25, 50, 35, 30, 15, 40, 30, 35, 45, 10, 20, 30, 25};
final int numItems = weights.length;
final int[] allItems = IntStream.range(0, numItems).toArray();
final double[] binCapacities = {100, 100, 100, 100, 100};
final int numBins = binCapacities.length;
final int[] allBins = IntStream.range(0, numBins).toArray();
// Create the linear solver with the SCIP backend.
MPSolver solver = MPSolver.createSolver("SCIP");
if (solver == null) {
System.out.println("Could not create solver SCIP");
return;
}
// Variables.
MPVariable[][] x = new MPVariable[numItems][numBins];
for (int i : allItems) {
for (int b : allBins) {
x[i][b] = solver.makeBoolVar("x_" + i + "_" + b);
}
}
// Constraints.
// Each item is assigned to at most one bin.
for (int i : allItems) {
MPConstraint constraint = solver.makeConstraint(0, 1, "");
for (int b : allBins) {
constraint.setCoefficient(x[i][b], 1);
}
}
// The amount packed in each bin cannot exceed its capacity.
for (int b : allBins) {
MPConstraint constraint = solver.makeConstraint(0, binCapacities[b], "");
for (int i : allItems) {
constraint.setCoefficient(x[i][b], weights[i]);
}
}
// Objective.
// Maximize total value of packed items.
MPObjective objective = solver.objective();
for (int i : allItems) {
for (int b : allBins) {
objective.setCoefficient(x[i][b], values[i]);
}
}
objective.setMaximization();
final MPSolver.ResultStatus status = solver.solve();
// Check that the problem has an optimal solution.
if (status == MPSolver.ResultStatus.OPTIMAL) {
System.out.println("Total packed value: " + objective.value());
double totalWeight = 0;
for (int b : allBins) {
double binWeight = 0;
double binValue = 0;
System.out.println("Bin " + b);
for (int i : allItems) {
if (x[i][b].solutionValue() == 1) {
System.out.println("Item " + i + " weight: " + weights[i] + " value: " + values[i]);
binWeight += weights[i];
binValue += values[i];
}
}
System.out.println("Packed bin weight: " + binWeight);
System.out.println("Packed bin value: " + binValue);
totalWeight += binWeight;
}
System.out.println("Total packed weight: " + totalWeight);
} else {
System.err.println("The problem does not have an optimal solution.");
}
}
private MultipleKnapsackMip() {}
}سی شارپ
// Solve a multiple knapsack problem using a MIP solver.
using System;
using System.Collections.Generic;
using System.Linq;
using Google.OrTools.LinearSolver;
public class MultipleKnapsackMip
{
public static void Main()
{
// Instantiate the data problem.
double[] Weights = { 48, 30, 42, 36, 36, 48, 42, 42, 36, 24, 30, 30, 42, 36, 36 };
double[] Values = { 10, 30, 25, 50, 35, 30, 15, 40, 30, 35, 45, 10, 20, 30, 25 };
int NumItems = Weights.Length;
int[] allItems = Enumerable.Range(0, NumItems).ToArray();
double[] BinCapacities = { 100, 100, 100, 100, 100 };
int NumBins = BinCapacities.Length;
int[] allBins = Enumerable.Range(0, NumBins).ToArray();
// Create the linear solver with the SCIP backend.
Solver solver = Solver.CreateSolver("SCIP");
if (solver is null)
{
return;
}
// Variables.
Variable[,] x = new Variable[NumItems, NumBins];
foreach (int i in allItems)
{
foreach (int b in allBins)
{
x[i, b] = solver.MakeBoolVar($"x_{i}_{b}");
}
}
// Constraints.
// Each item is assigned to at most one bin.
foreach (int i in allItems)
{
Constraint constraint = solver.MakeConstraint(0, 1, "");
foreach (int b in allBins)
{
constraint.SetCoefficient(x[i, b], 1);
}
}
// The amount packed in each bin cannot exceed its capacity.
foreach (int b in allBins)
{
Constraint constraint = solver.MakeConstraint(0, BinCapacities[b], "");
foreach (int i in allItems)
{
constraint.SetCoefficient(x[i, b], Weights[i]);
}
}
// Objective.
Objective objective = solver.Objective();
foreach (int i in allItems)
{
foreach (int b in allBins)
{
objective.SetCoefficient(x[i, b], Values[i]);
}
}
objective.SetMaximization();
Solver.ResultStatus resultStatus = solver.Solve();
// Check that the problem has an optimal solution.
if (resultStatus == Solver.ResultStatus.OPTIMAL)
{
Console.WriteLine($"Total packed value: {solver.Objective().Value()}");
double TotalWeight = 0.0;
foreach (int b in allBins)
{
double BinWeight = 0.0;
double BinValue = 0.0;
Console.WriteLine("Bin " + b);
foreach (int i in allItems)
{
if (x[i, b].SolutionValue() == 1)
{
Console.WriteLine($"Item {i} weight: {Weights[i]} values: {Values[i]}");
BinWeight += Weights[i];
BinValue += Values[i];
}
}
Console.WriteLine("Packed bin weight: " + BinWeight);
Console.WriteLine("Packed bin value: " + BinValue);
TotalWeight += BinWeight;
}
Console.WriteLine("Total packed weight: " + TotalWeight);
}
else
{
Console.WriteLine("The problem does not have an optimal solution!");
}
}
}راه حل CP SAT
بخش های زیر نحوه حل مشکل با استفاده از حل کننده CP-SAT را شرح می دهد.
کتابخانه ها را وارد کنید
کد زیر کتابخانه های مورد نیاز را وارد می کند.
پایتون
from ortools.sat.python import cp_model
C++
#include <stdlib.h> #include <map> #include <numeric> #include <tuple> #include <vector> #include "absl/strings/str_format.h" #include "ortools/base/logging.h" #include "ortools/sat/cp_model.h" #include "ortools/sat/cp_model.pb.h" #include "ortools/sat/cp_model_solver.h"
جاوا
import com.google.ortools.Loader; import com.google.ortools.sat.CpModel; import com.google.ortools.sat.CpSolver; import com.google.ortools.sat.CpSolverStatus; import com.google.ortools.sat.LinearExpr; import com.google.ortools.sat.LinearExprBuilder; import com.google.ortools.sat.Literal; import java.util.ArrayList; import java.util.List; import java.util.stream.IntStream;
سی شارپ
using System;
using System.Collections.Generic;
using System.Linq;
using Google.OrTools.Sat;
public class MultipleKnapsackSat
{
public static void Main(String[] args)
{
// Instantiate the data problem.
int[] Weights = { 48, 30, 42, 36, 36, 48, 42, 42, 36, 24, 30, 30, 42, 36, 36 };
int[] Values = { 10, 30, 25, 50, 35, 30, 15, 40, 30, 35, 45, 10, 20, 30, 25 };
int NumItems = Weights.Length;
int[] allItems = Enumerable.Range(0, NumItems).ToArray();
int[] BinCapacities = { 100, 100, 100, 100, 100 };
int NumBins = BinCapacities.Length;
int[] allBins = Enumerable.Range(0, NumBins).ToArray();
// Model.
CpModel model = new CpModel();
// Variables.
ILiteral[,] x = new ILiteral[NumItems, NumBins];
foreach (int i in allItems)
{
foreach (int b in allBins)
{
x[i, b] = model.NewBoolVar($"x_{i}_{b}");
}
}
// Constraints.
// Each item is assigned to at most one bin.
foreach (int i in allItems)
{
List<ILiteral> literals = new List<ILiteral>();
foreach (int b in allBins)
{
literals.Add(x[i, b]);
}
model.AddAtMostOne(literals);
}
// The amount packed in each bin cannot exceed its capacity.
foreach (int b in allBins)
{
List<ILiteral> items = new List<ILiteral>();
foreach (int i in allItems)
{
items.Add(x[i, b]);
}
model.Add(LinearExpr.WeightedSum(items, Weights) <= BinCapacities[b]);
}
// Objective.
LinearExprBuilder obj = LinearExpr.NewBuilder();
foreach (int i in allItems)
{
foreach (int b in allBins)
{
obj.AddTerm(x[i, b], Values[i]);
}
}
model.Maximize(obj);
// Solve
CpSolver solver = new CpSolver();
CpSolverStatus status = solver.Solve(model);
// Print solution.
// Check that the problem has a feasible solution.
if (status == CpSolverStatus.Optimal || status == CpSolverStatus.Feasible)
{
Console.WriteLine($"Total packed value: {solver.ObjectiveValue}");
double TotalWeight = 0.0;
foreach (int b in allBins)
{
double BinWeight = 0.0;
double BinValue = 0.0;
Console.WriteLine($"Bin {b}");
foreach (int i in allItems)
{
if (solver.BooleanValue(x[i, b]))
{
Console.WriteLine($"Item {i} weight: {Weights[i]} values: {Values[i]}");
BinWeight += Weights[i];
BinValue += Values[i];
}
}
Console.WriteLine("Packed bin weight: " + BinWeight);
Console.WriteLine("Packed bin value: " + BinValue);
TotalWeight += BinWeight;
}
Console.WriteLine("Total packed weight: " + TotalWeight);
}
else
{
Console.WriteLine("No solution found.");
}
Console.WriteLine("Statistics");
Console.WriteLine($" conflicts: {solver.NumConflicts()}");
Console.WriteLine($" branches : {solver.NumBranches()}");
Console.WriteLine($" wall time: {solver.WallTime()}s");
}
}
مدل را اعلام کنید
کد زیر مدل CP-SAT را اعلام می کند.
پایتون
model = cp_model.CpModel()
C++
CpModelBuilder cp_model;
جاوا
CpModel model = new CpModel();
سی شارپ
CpModel model = new CpModel();
داده ها را ایجاد کنید
کد زیر داده های مشکل را تنظیم می کند.
پایتون
data = {}
data["weights"] = [48, 30, 42, 36, 36, 48, 42, 42, 36, 24, 30, 30, 42, 36, 36]
data["values"] = [10, 30, 25, 50, 35, 30, 15, 40, 30, 35, 45, 10, 20, 30, 25]
assert len(data["weights"]) == len(data["values"])
num_items = len(data["weights"])
all_items = range(num_items)
data["bin_capacities"] = [100, 100, 100, 100, 100]
num_bins = len(data["bin_capacities"])
all_bins = range(num_bins)C++
const std::vector<int> weights = {
{48, 30, 42, 36, 36, 48, 42, 42, 36, 24, 30, 30, 42, 36, 36}};
const std::vector<int> values = {
{10, 30, 25, 50, 35, 30, 15, 40, 30, 35, 45, 10, 20, 30, 25}};
const int num_items = static_cast<int>(weights.size());
std::vector<int> all_items(num_items);
std::iota(all_items.begin(), all_items.end(), 0);
const std::vector<int> bin_capacities = {{100, 100, 100, 100, 100}};
const int num_bins = static_cast<int>(bin_capacities.size());
std::vector<int> all_bins(num_bins);
std::iota(all_bins.begin(), all_bins.end(), 0);جاوا
final int[] weights = {48, 30, 42, 36, 36, 48, 42, 42, 36, 24, 30, 30, 42, 36, 36};
final int[] values = {10, 30, 25, 50, 35, 30, 15, 40, 30, 35, 45, 10, 20, 30, 25};
final int numItems = weights.length;
final int[] allItems = IntStream.range(0, numItems).toArray();
final int[] binCapacities = {100, 100, 100, 100, 100};
final int numBins = binCapacities.length;
final int[] allBins = IntStream.range(0, numBins).toArray();سی شارپ
int[] Weights = { 48, 30, 42, 36, 36, 48, 42, 42, 36, 24, 30, 30, 42, 36, 36 };
int[] Values = { 10, 30, 25, 50, 35, 30, 15, 40, 30, 35, 45, 10, 20, 30, 25 };
int NumItems = Weights.Length;
int[] allItems = Enumerable.Range(0, NumItems).ToArray();
int[] BinCapacities = { 100, 100, 100, 100, 100 };
int NumBins = BinCapacities.Length;
int[] allBins = Enumerable.Range(0, NumBins).ToArray(); آرایه costs مربوط به جدول هزینه ها برای تخصیص کارگران به وظایف است که در بالا نشان داده شده است.
متغیرها را ایجاد کنید
کد زیر متغیرهای عدد صحیح باینری را برای مشکل ایجاد می کند.
پایتون
# x[i, b] = 1 if item i is packed in bin b.
x = {}
for i in all_items:
for b in all_bins:
x[i, b] = model.new_bool_var(f"x_{i}_{b}")C++
// x[i, b] = 1 if item i is packed in bin b.
std::map<std::tuple<int, int>, BoolVar> x;
for (int i : all_items) {
for (int b : all_bins) {
auto key = std::make_tuple(i, b);
x[key] = cp_model.NewBoolVar().WithName(absl::StrFormat("x_%d_%d", i, b));
}
}جاوا
Literal[][] x = new Literal[numItems][numBins];
for (int i : allItems) {
for (int b : allBins) {
x[i][b] = model.newBoolVar("x_" + i + "_" + b);
}
}سی شارپ
ILiteral[,] x = new ILiteral[NumItems, NumBins];
foreach (int i in allItems)
{
foreach (int b in allBins)
{
x[i, b] = model.NewBoolVar($"x_{i}_{b}");
}
}محدودیت ها را ایجاد کنید
کد زیر محدودیت هایی را برای مشکل ایجاد می کند.
پایتون
# Each item is assigned to at most one bin.
for i in all_items:
model.add_at_most_one(x[i, b] for b in all_bins)
# The amount packed in each bin cannot exceed its capacity.
for b in all_bins:
model.add(
sum(x[i, b] * data["weights"][i] for i in all_items)
<= data["bin_capacities"][b]
)C++
// Each item is assigned to at most one bin.
for (int i : all_items) {
std::vector<BoolVar> copies;
for (int b : all_bins) {
copies.push_back(x[std::make_tuple(i, b)]);
}
cp_model.AddAtMostOne(copies);
}
// The amount packed in each bin cannot exceed its capacity.
for (int b : all_bins) {
LinearExpr bin_weight;
for (int i : all_items) {
bin_weight += x[std::make_tuple(i, b)] * weights[i];
}
cp_model.AddLessOrEqual(bin_weight, bin_capacities[b]);
}جاوا
// Each item is assigned to at most one bin.
for (int i : allItems) {
List<Literal> bins = new ArrayList<>();
for (int b : allBins) {
bins.add(x[i][b]);
}
model.addAtMostOne(bins);
}
// The amount packed in each bin cannot exceed its capacity.
for (int b : allBins) {
LinearExprBuilder load = LinearExpr.newBuilder();
for (int i : allItems) {
load.addTerm(x[i][b], weights[i]);
}
model.addLessOrEqual(load, binCapacities[b]);
}سی شارپ
// Each item is assigned to at most one bin.
foreach (int i in allItems)
{
List<ILiteral> literals = new List<ILiteral>();
foreach (int b in allBins)
{
literals.Add(x[i, b]);
}
model.AddAtMostOne(literals);
}
// The amount packed in each bin cannot exceed its capacity.
foreach (int b in allBins)
{
List<ILiteral> items = new List<ILiteral>();
foreach (int i in allItems)
{
items.Add(x[i, b]);
}
model.Add(LinearExpr.WeightedSum(items, Weights) <= BinCapacities[b]);
}تابع هدف را ایجاد کنید
کد زیر تابع هدف مشکل را ایجاد می کند.
پایتون
# maximize total value of packed items.
objective = []
for i in all_items:
for b in all_bins:
objective.append(cp_model.LinearExpr.term(x[i, b], data["values"][i]))
model.maximize(cp_model.LinearExpr.sum(objective))C++
// Maximize total value of packed items.
LinearExpr objective;
for (int i : all_items) {
for (int b : all_bins) {
objective += x[std::make_tuple(i, b)] * values[i];
}
}
cp_model.Maximize(objective);جاوا
// Maximize total value of packed items.
LinearExprBuilder obj = LinearExpr.newBuilder();
for (int i : allItems) {
for (int b : allBins) {
obj.addTerm(x[i][b], values[i]);
}
}
model.maximize(obj);سی شارپ
LinearExprBuilder obj = LinearExpr.NewBuilder();
foreach (int i in allItems)
{
foreach (int b in allBins)
{
obj.AddTerm(x[i, b], Values[i]);
}
}
model.Maximize(obj);مقدار تابع هدف کل هزینه تمام متغیرهایی است که توسط حل کننده مقدار 1 به آنها اختصاص داده شده است.
حل کننده را فراخوانی کنید
کد زیر حل کننده را فراخوانی می کند.
پایتون
solver = cp_model.CpSolver() status = solver.solve(model)
C++
const CpSolverResponse response = Solve(cp_model.Build());
جاوا
CpSolver solver = new CpSolver(); final CpSolverStatus status = solver.solve(model);
سی شارپ
CpSolver solver = new CpSolver(); CpSolverStatus status = solver.Solve(model);
محلول را چاپ کنید
کد زیر راه حل مشکل را چاپ می کند.
پایتون
if status == cp_model.OPTIMAL:
print(f"Total packed value: {solver.objective_value}")
total_weight = 0
for b in all_bins:
print(f"Bin {b}")
bin_weight = 0
bin_value = 0
for i in all_items:
if solver.value(x[i, b]) > 0:
print(
f'Item:{i} weight:{data["weights"][i]} value:{data["values"][i]}'
)
bin_weight += data["weights"][i]
bin_value += data["values"][i]
print(f"Packed bin weight: {bin_weight}")
print(f"Packed bin value: {bin_value}\n")
total_weight += bin_weight
print(f"Total packed weight: {total_weight}")
else:
print("The problem does not have an optimal solution.")C++
if (response.status() == CpSolverStatus::OPTIMAL ||
response.status() == CpSolverStatus::FEASIBLE) {
LOG(INFO) << "Total packed value: " << response.objective_value();
double total_weight = 0.0;
for (int b : all_bins) {
LOG(INFO) << "Bin " << b;
double bin_weight = 0.0;
double bin_value = 0.0;
for (int i : all_items) {
auto key = std::make_tuple(i, b);
if (SolutionIntegerValue(response, x[key]) > 0) {
LOG(INFO) << "Item " << i << " weight: " << weights[i]
<< " value: " << values[i];
bin_weight += weights[i];
bin_value += values[i];
}
}
LOG(INFO) << "Packed bin weight: " << bin_weight;
LOG(INFO) << "Packed bin value: " << bin_value;
total_weight += bin_weight;
}
LOG(INFO) << "Total packed weight: " << total_weight;
} else {
LOG(INFO) << "The problem does not have an optimal solution.";
}جاوا
// Check that the problem has an optimal solution.
if (status == CpSolverStatus.OPTIMAL) {
System.out.println("Total packed value: " + solver.objectiveValue());
long totalWeight = 0;
for (int b : allBins) {
long binWeight = 0;
long binValue = 0;
System.out.println("Bin " + b);
for (int i : allItems) {
if (solver.booleanValue(x[i][b])) {
System.out.println("Item " + i + " weight: " + weights[i] + " value: " + values[i]);
binWeight += weights[i];
binValue += values[i];
}
}
System.out.println("Packed bin weight: " + binWeight);
System.out.println("Packed bin value: " + binValue);
totalWeight += binWeight;
}
System.out.println("Total packed weight: " + totalWeight);
} else {
System.err.println("The problem does not have an optimal solution.");
}سی شارپ
// Check that the problem has a feasible solution.
if (status == CpSolverStatus.Optimal || status == CpSolverStatus.Feasible)
{
Console.WriteLine($"Total packed value: {solver.ObjectiveValue}");
double TotalWeight = 0.0;
foreach (int b in allBins)
{
double BinWeight = 0.0;
double BinValue = 0.0;
Console.WriteLine($"Bin {b}");
foreach (int i in allItems)
{
if (solver.BooleanValue(x[i, b]))
{
Console.WriteLine($"Item {i} weight: {Weights[i]} values: {Values[i]}");
BinWeight += Weights[i];
BinValue += Values[i];
}
}
Console.WriteLine("Packed bin weight: " + BinWeight);
Console.WriteLine("Packed bin value: " + BinValue);
TotalWeight += BinWeight;
}
Console.WriteLine("Total packed weight: " + TotalWeight);
}
else
{
Console.WriteLine("No solution found.");
}اینم خروجی برنامه
Total packed value: 395.0 Bin 0 Item 3 - weight: 36 value: 50 Item 13 - weight: 36 value: 30 Packed bin weight: 72 Packed bin value: 80 Bin 1 Item 5 - weight: 48 value: 30 Item 7 - weight: 42 value: 40 Packed bin weight: 90 Packed bin value: 70 Bin 2 Item 1 - weight: 30 value: 30 Item 10 - weight: 30 value: 45 Item 14 - weight: 36 value: 25 Packed bin weight: 96 Packed bin value: 100 Bin 3 Item 2 - weight: 42 value: 25 Item 12 - weight: 42 value: 20 Packed bin weight: 84 Packed bin value: 45 Bin 4 Item 4 - weight: 36 value: 35 Item 8 - weight: 36 value: 30 Item 9 - weight: 24 value: 35 Packed bin weight: 96 Packed bin value: 100 Total packed weight: 438
برنامه های کامل
در اینجا برنامه های کامل برای راه حل CP-SAT آمده است.
پایتون
"""Solves a multiple knapsack problem using the CP-SAT solver."""
from ortools.sat.python import cp_model
def main() -> None:
data = {}
data["weights"] = [48, 30, 42, 36, 36, 48, 42, 42, 36, 24, 30, 30, 42, 36, 36]
data["values"] = [10, 30, 25, 50, 35, 30, 15, 40, 30, 35, 45, 10, 20, 30, 25]
assert len(data["weights"]) == len(data["values"])
num_items = len(data["weights"])
all_items = range(num_items)
data["bin_capacities"] = [100, 100, 100, 100, 100]
num_bins = len(data["bin_capacities"])
all_bins = range(num_bins)
model = cp_model.CpModel()
# Variables.
# x[i, b] = 1 if item i is packed in bin b.
x = {}
for i in all_items:
for b in all_bins:
x[i, b] = model.new_bool_var(f"x_{i}_{b}")
# Constraints.
# Each item is assigned to at most one bin.
for i in all_items:
model.add_at_most_one(x[i, b] for b in all_bins)
# The amount packed in each bin cannot exceed its capacity.
for b in all_bins:
model.add(
sum(x[i, b] * data["weights"][i] for i in all_items)
<= data["bin_capacities"][b]
)
# Objective.
# maximize total value of packed items.
objective = []
for i in all_items:
for b in all_bins:
objective.append(cp_model.LinearExpr.term(x[i, b], data["values"][i]))
model.maximize(cp_model.LinearExpr.sum(objective))
solver = cp_model.CpSolver()
status = solver.solve(model)
if status == cp_model.OPTIMAL:
print(f"Total packed value: {solver.objective_value}")
total_weight = 0
for b in all_bins:
print(f"Bin {b}")
bin_weight = 0
bin_value = 0
for i in all_items:
if solver.value(x[i, b]) > 0:
print(
f'Item:{i} weight:{data["weights"][i]} value:{data["values"][i]}'
)
bin_weight += data["weights"][i]
bin_value += data["values"][i]
print(f"Packed bin weight: {bin_weight}")
print(f"Packed bin value: {bin_value}\n")
total_weight += bin_weight
print(f"Total packed weight: {total_weight}")
else:
print("The problem does not have an optimal solution.")
if __name__ == "__main__":
main()C++
// Solves a multiple knapsack problem using the CP-SAT solver.
#include <stdlib.h>
#include <map>
#include <numeric>
#include <tuple>
#include <vector>
#include "absl/strings/str_format.h"
#include "ortools/base/logging.h"
#include "ortools/sat/cp_model.h"
#include "ortools/sat/cp_model.pb.h"
#include "ortools/sat/cp_model_solver.h"
namespace operations_research {
namespace sat {
void MultipleKnapsackSat() {
const std::vector<int> weights = {
{48, 30, 42, 36, 36, 48, 42, 42, 36, 24, 30, 30, 42, 36, 36}};
const std::vector<int> values = {
{10, 30, 25, 50, 35, 30, 15, 40, 30, 35, 45, 10, 20, 30, 25}};
const int num_items = static_cast<int>(weights.size());
std::vector<int> all_items(num_items);
std::iota(all_items.begin(), all_items.end(), 0);
const std::vector<int> bin_capacities = {{100, 100, 100, 100, 100}};
const int num_bins = static_cast<int>(bin_capacities.size());
std::vector<int> all_bins(num_bins);
std::iota(all_bins.begin(), all_bins.end(), 0);
CpModelBuilder cp_model;
// Variables.
// x[i, b] = 1 if item i is packed in bin b.
std::map<std::tuple<int, int>, BoolVar> x;
for (int i : all_items) {
for (int b : all_bins) {
auto key = std::make_tuple(i, b);
x[key] = cp_model.NewBoolVar().WithName(absl::StrFormat("x_%d_%d", i, b));
}
}
// Constraints.
// Each item is assigned to at most one bin.
for (int i : all_items) {
std::vector<BoolVar> copies;
for (int b : all_bins) {
copies.push_back(x[std::make_tuple(i, b)]);
}
cp_model.AddAtMostOne(copies);
}
// The amount packed in each bin cannot exceed its capacity.
for (int b : all_bins) {
LinearExpr bin_weight;
for (int i : all_items) {
bin_weight += x[std::make_tuple(i, b)] * weights[i];
}
cp_model.AddLessOrEqual(bin_weight, bin_capacities[b]);
}
// Objective.
// Maximize total value of packed items.
LinearExpr objective;
for (int i : all_items) {
for (int b : all_bins) {
objective += x[std::make_tuple(i, b)] * values[i];
}
}
cp_model.Maximize(objective);
const CpSolverResponse response = Solve(cp_model.Build());
if (response.status() == CpSolverStatus::OPTIMAL ||
response.status() == CpSolverStatus::FEASIBLE) {
LOG(INFO) << "Total packed value: " << response.objective_value();
double total_weight = 0.0;
for (int b : all_bins) {
LOG(INFO) << "Bin " << b;
double bin_weight = 0.0;
double bin_value = 0.0;
for (int i : all_items) {
auto key = std::make_tuple(i, b);
if (SolutionIntegerValue(response, x[key]) > 0) {
LOG(INFO) << "Item " << i << " weight: " << weights[i]
<< " value: " << values[i];
bin_weight += weights[i];
bin_value += values[i];
}
}
LOG(INFO) << "Packed bin weight: " << bin_weight;
LOG(INFO) << "Packed bin value: " << bin_value;
total_weight += bin_weight;
}
LOG(INFO) << "Total packed weight: " << total_weight;
} else {
LOG(INFO) << "The problem does not have an optimal solution.";
}
// Statistics.
LOG(INFO) << "Statistics";
LOG(INFO) << CpSolverResponseStats(response);
}
} // namespace sat
} // namespace operations_research
int main() {
operations_research::sat::MultipleKnapsackSat();
return EXIT_SUCCESS;
}جاوا
// Solves a multiple knapsack problem using the CP-SAT solver.
package com.google.ortools.sat.samples;
import com.google.ortools.Loader;
import com.google.ortools.sat.CpModel;
import com.google.ortools.sat.CpSolver;
import com.google.ortools.sat.CpSolverStatus;
import com.google.ortools.sat.LinearExpr;
import com.google.ortools.sat.LinearExprBuilder;
import com.google.ortools.sat.Literal;
import java.util.ArrayList;
import java.util.List;
import java.util.stream.IntStream;
/** Sample showing how to solve a multiple knapsack problem. */
public class MultipleKnapsackSat {
public static void main(String[] args) {
Loader.loadNativeLibraries();
// Instantiate the data problem.
final int[] weights = {48, 30, 42, 36, 36, 48, 42, 42, 36, 24, 30, 30, 42, 36, 36};
final int[] values = {10, 30, 25, 50, 35, 30, 15, 40, 30, 35, 45, 10, 20, 30, 25};
final int numItems = weights.length;
final int[] allItems = IntStream.range(0, numItems).toArray();
final int[] binCapacities = {100, 100, 100, 100, 100};
final int numBins = binCapacities.length;
final int[] allBins = IntStream.range(0, numBins).toArray();
CpModel model = new CpModel();
// Variables.
Literal[][] x = new Literal[numItems][numBins];
for (int i : allItems) {
for (int b : allBins) {
x[i][b] = model.newBoolVar("x_" + i + "_" + b);
}
}
// Constraints.
// Each item is assigned to at most one bin.
for (int i : allItems) {
List<Literal> bins = new ArrayList<>();
for (int b : allBins) {
bins.add(x[i][b]);
}
model.addAtMostOne(bins);
}
// The amount packed in each bin cannot exceed its capacity.
for (int b : allBins) {
LinearExprBuilder load = LinearExpr.newBuilder();
for (int i : allItems) {
load.addTerm(x[i][b], weights[i]);
}
model.addLessOrEqual(load, binCapacities[b]);
}
// Objective.
// Maximize total value of packed items.
LinearExprBuilder obj = LinearExpr.newBuilder();
for (int i : allItems) {
for (int b : allBins) {
obj.addTerm(x[i][b], values[i]);
}
}
model.maximize(obj);
CpSolver solver = new CpSolver();
final CpSolverStatus status = solver.solve(model);
// Check that the problem has an optimal solution.
if (status == CpSolverStatus.OPTIMAL) {
System.out.println("Total packed value: " + solver.objectiveValue());
long totalWeight = 0;
for (int b : allBins) {
long binWeight = 0;
long binValue = 0;
System.out.println("Bin " + b);
for (int i : allItems) {
if (solver.booleanValue(x[i][b])) {
System.out.println("Item " + i + " weight: " + weights[i] + " value: " + values[i]);
binWeight += weights[i];
binValue += values[i];
}
}
System.out.println("Packed bin weight: " + binWeight);
System.out.println("Packed bin value: " + binValue);
totalWeight += binWeight;
}
System.out.println("Total packed weight: " + totalWeight);
} else {
System.err.println("The problem does not have an optimal solution.");
}
}
private MultipleKnapsackSat() {}
}سی شارپ
// Solves a multiple knapsack problem using the CP-SAT solver.
using System;
using System.Collections.Generic;
using System.Linq;
using Google.OrTools.Sat;
public class MultipleKnapsackSat
{
public static void Main(String[] args)
{
// Instantiate the data problem.
int[] Weights = { 48, 30, 42, 36, 36, 48, 42, 42, 36, 24, 30, 30, 42, 36, 36 };
int[] Values = { 10, 30, 25, 50, 35, 30, 15, 40, 30, 35, 45, 10, 20, 30, 25 };
int NumItems = Weights.Length;
int[] allItems = Enumerable.Range(0, NumItems).ToArray();
int[] BinCapacities = { 100, 100, 100, 100, 100 };
int NumBins = BinCapacities.Length;
int[] allBins = Enumerable.Range(0, NumBins).ToArray();
// Model.
CpModel model = new CpModel();
// Variables.
ILiteral[,] x = new ILiteral[NumItems, NumBins];
foreach (int i in allItems)
{
foreach (int b in allBins)
{
x[i, b] = model.NewBoolVar($"x_{i}_{b}");
}
}
// Constraints.
// Each item is assigned to at most one bin.
foreach (int i in allItems)
{
List<ILiteral> literals = new List<ILiteral>();
foreach (int b in allBins)
{
literals.Add(x[i, b]);
}
model.AddAtMostOne(literals);
}
// The amount packed in each bin cannot exceed its capacity.
foreach (int b in allBins)
{
List<ILiteral> items = new List<ILiteral>();
foreach (int i in allItems)
{
items.Add(x[i, b]);
}
model.Add(LinearExpr.WeightedSum(items, Weights) <= BinCapacities[b]);
}
// Objective.
LinearExprBuilder obj = LinearExpr.NewBuilder();
foreach (int i in allItems)
{
foreach (int b in allBins)
{
obj.AddTerm(x[i, b], Values[i]);
}
}
model.Maximize(obj);
// Solve
CpSolver solver = new CpSolver();
CpSolverStatus status = solver.Solve(model);
// Print solution.
// Check that the problem has a feasible solution.
if (status == CpSolverStatus.Optimal || status == CpSolverStatus.Feasible)
{
Console.WriteLine($"Total packed value: {solver.ObjectiveValue}");
double TotalWeight = 0.0;
foreach (int b in allBins)
{
double BinWeight = 0.0;
double BinValue = 0.0;
Console.WriteLine($"Bin {b}");
foreach (int i in allItems)
{
if (solver.BooleanValue(x[i, b]))
{
Console.WriteLine($"Item {i} weight: {Weights[i]} values: {Values[i]}");
BinWeight += Weights[i];
BinValue += Values[i];
}
}
Console.WriteLine("Packed bin weight: " + BinWeight);
Console.WriteLine("Packed bin value: " + BinValue);
TotalWeight += BinWeight;
}
Console.WriteLine("Total packed weight: " + TotalWeight);
}
else
{
Console.WriteLine("No solution found.");
}
Console.WriteLine("Statistics");
Console.WriteLine($" conflicts: {solver.NumConflicts()}");
Console.WriteLine($" branches : {solver.NumBranches()}");
Console.WriteLine($" wall time: {solver.WallTime()}s");
}
}