Stay organized with collections
Save and categorize content based on your preferences.
blockly > utils > dom > removeNode
utils.dom.removeNode() function
Removes a node from its parent. No-op if not attached to a parent.
Signature:
export declare function removeNode(node: Node | null): Node | null;
Parameters
| Parameter |
Type |
Description |
| node |
Node | null |
The node to remove. |
Returns:
Node | null
The node removed if removed; else, null.
Except as otherwise noted, the content of this page is licensed under the Creative Commons Attribution 4.0 License, and code samples are licensed under the Apache 2.0 License. For details, see the Google Developers Site Policies. Java is a registered trademark of Oracle and/or its affiliates.
Last updated 2024-09-18 UTC.
[[["Easy to understand","easyToUnderstand","thumb-up"],["Solved my problem","solvedMyProblem","thumb-up"],["Other","otherUp","thumb-up"]],[["Missing the information I need","missingTheInformationINeed","thumb-down"],["Too complicated / too many steps","tooComplicatedTooManySteps","thumb-down"],["Out of date","outOfDate","thumb-down"],["Samples / code issue","samplesCodeIssue","thumb-down"],["Other","otherDown","thumb-down"]],["Last updated 2024-09-18 UTC."],[[["Removes a specified node from its parent in the DOM."],["Returns the removed node, or null if the node was not attached to a parent."],["Utilizes the `removeNode()` function within the `Blockly.utils.dom` namespace for this operation."],["Accepts a single argument: the node to be removed."],["If the provided node is not attached to a parent element, the function does nothing."]]],[]]
