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blockly > ASTNode > out
ASTNode.out() method
Find the next element that is one position above and all the way to the left of the current location.
Signature:
out(): ASTNode | null;
Returns:
ASTNode | null
An AST node that wraps the next field, connection, workspace or block. Or null if we are at the workspace level.
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Last updated 2024-09-18 UTC.
[[["Easy to understand","easyToUnderstand","thumb-up"],["Solved my problem","solvedMyProblem","thumb-up"],["Other","otherUp","thumb-up"]],[["Missing the information I need","missingTheInformationINeed","thumb-down"],["Too complicated / too many steps","tooComplicatedTooManySteps","thumb-down"],["Out of date","outOfDate","thumb-down"],["Samples / code issue","samplesCodeIssue","thumb-down"],["Other","otherDown","thumb-down"]],["Last updated 2024-09-18 UTC."],[[["The `ASTNode.out()` method is used to navigate the Abstract Syntax Tree (AST) structure."],["It locates and returns the AST node that is positioned one level above and to the extreme left of the current node."],["If the current node is at the workspace level, signifying the top-most level of the AST, it returns null."]]],[]]
