isDraggable() 函数
返回指定对象是否可 ID。
Signature:
export declare function isDraggable(obj: any): obj is IDraggable;
参数
| 参数 | 类型 | 说明 |
|---|---|---|
| obj | 任意 |
返回：
obj 为 IDraggable
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最后更新时间 (UTC)：2025-07-25。
[[["易于理解","easyToUnderstand","thumb-up"],["解决了我的问题","solvedMyProblem","thumb-up"],["其他","otherUp","thumb-up"]],[["没有我需要的信息","missingTheInformationINeed","thumb-down"],["太复杂/步骤太多","tooComplicatedTooManySteps","thumb-down"],["内容需要更新","outOfDate","thumb-down"],["翻译问题","translationIssue","thumb-down"],["示例/代码问题","samplesCodeIssue","thumb-down"],["其他","otherDown","thumb-down"]],["最后更新时间 (UTC)：2025-07-25。"],[],["The `isDraggable()` function determines if an object is of the `IDraggable` type. It accepts a single parameter, `obj` of any type, and returns a boolean indicating whether `obj` conforms to the `IDraggable` interface. The function's core purpose is to check the object's type against `IDraggable`. It is declared as an exported function.\n"]]