Google Knowledge Graph Search API

知識圖譜 Search API 可讓您在 Google 知識圖譜中尋找實體。API 使用標準的 schema.org 類型，且符合 JSON-LD 規格。

典型應用實例

以下舉例說明如何使用 Knowledge Graph Search API：

  • 取得符合特定條件且最有名的實體排名清單。
  • 搜尋框中預測完成的實體。
  • 使用知識圖譜實體為內容加上註解/整理。

如要進一步瞭解 API 方法和參數，請參閱 API 參考資料。

要求範例

下列範例顯示您可以傳送至 API 的要求類型。(但請先參閱事前準備一節，此外，您還必須插入自己的 API 金鑰。)

https://kgsearch.googleapis.com/v1/entities:search?query=taylor+swift&key=API_KEY&limit=1&indent=True

上述範例搜尋會傳回類似以下的 JSON-LD 結果：

{
  "@context": {
    "@vocab": "http://schema.org/",
    "goog": "http://schema.googleapis.com/",
    "resultScore": "goog:resultScore",
    "detailedDescription": "goog:detailedDescription",
    "EntitySearchResult": "goog:EntitySearchResult",
    "kg": "http://g.co/kg"
  },
  "@type": "ItemList",
  "itemListElement": [
    {
      "@type": "EntitySearchResult",
      "result": {
        "@id": "kg:/m/0dl567",
        "name": "Taylor Swift",
        "@type": [
          "Thing",
          "Person"
        ],
        "description": "Singer-songwriter",
        "image": {
          "contentUrl": "https://t1.gstatic.com/images?q=tbn:ANd9GcQmVDAhjhWnN2OWys2ZMO3PGAhupp5tN2LwF_BJmiHgi19hf8Ku",
          "url": "https://en.wikipedia.org/wiki/Taylor_Swift",
          "license": "http://creativecommons.org/licenses/by-sa/2.0"
        },
        "detailedDescription": {
          "articleBody": "Taylor Alison Swift is an American singer-songwriter and actress. Raised in Wyomissing, Pennsylvania, she moved to Nashville, Tennessee, at the age of 14 to pursue a career in country music. ",
          "url": "http://en.wikipedia.org/wiki/Taylor_Swift",
          "license": "https://en.wikipedia.org/wiki/Wikipedia:Text_of_Creative_Commons_Attribution-ShareAlike_3.0_Unported_License"
        },
        "url": "http://taylorswift.com/"
      },
      "resultScore": 4850
    }
  ]
}

以下程式碼範例顯示如何以各種支援的語言執行類似的搜尋。此搜尋會傳回與 Taylor Swift 相符的項目。

Python

"""Example of Python client calling Knowledge Graph Search API."""
import json
import urllib

api_key = open('.api_key').read()
query = 'Taylor Swift'
service_url = 'https://kgsearch.googleapis.com/v1/entities:search'
params = {
    'query': query,
    'limit': 10,
    'indent': True,
    'key': api_key,
}
url = service_url + '?' + urllib.urlencode(params)
response = json.loads(urllib.urlopen(url).read())
for element in response['itemListElement']:
  print(element['result']['name'] + ' (' + str(element['resultScore']) + ')')

Java

package com.google.knowledge.platforms.syndication.entitymatch.codesample;

import com.google.api.client.http.GenericUrl;
import com.google.api.client.http.HttpRequest;
import com.google.api.client.http.HttpRequestFactory;
import com.google.api.client.http.HttpResponse;
import com.google.api.client.http.HttpTransport;
import com.google.api.client.http.javanet.NetHttpTransport;
import com.jayway.jsonpath.JsonPath;
import java.io.FileInputStream;
import java.util.Properties;
import org.json.simple.JSONArray;
import org.json.simple.JSONObject;
import org.json.simple.parser.JSONParser;

/** Example of Java client calling Knowledge Graph Search API */
public class SearchExample {
  public static Properties properties = new Properties();
  public static void main(String[] args) {
    try {
      properties.load(new FileInputStream("kgsearch.properties"));

      HttpTransport httpTransport = new NetHttpTransport();
      HttpRequestFactory requestFactory = httpTransport.createRequestFactory();
      JSONParser parser = new JSONParser();
      GenericUrl url = new GenericUrl("https://kgsearch.googleapis.com/v1/entities:search");
      url.put("query", "Taylor Swift");
      url.put("limit", "10");
      url.put("indent", "true");
      url.put("key", properties.get("API_KEY"));
      HttpRequest request = requestFactory.buildGetRequest(url);
      HttpResponse httpResponse = request.execute();
      JSONObject response = (JSONObject) parser.parse(httpResponse.parseAsString());
      JSONArray elements = (JSONArray) response.get("itemListElement");
      for (Object element : elements) {
        System.out.println(JsonPath.read(element, "$.result.name").toString());
      }
    } catch (Exception ex) {
      ex.printStackTrace();
    }
  }
}

JavaScript

<!DOCTYPE html>
<html>
<head>
    <script src="http://ajax.googleapis.com/ajax/libs/jquery/2.1.4/jquery.min.js"></script>
</head>
<body>
<script>
  var service_url = 'https://kgsearch.googleapis.com/v1/entities:search';
  var params = {
    'query': 'Taylor Swift',
    'limit': 10,
    'indent': true,
    'key' : '<put your api_key here>',
  };
  $.getJSON(service_url + '?callback=?', params, function(response) {
    $.each(response.itemListElement, function(i, element) {
      $('<div>', {text:element['result']['name']}).appendTo(document.body);
    });
  });
</script>
</body>
</html>

PHP

<?php
require '.api_key';
$service_url = 'https://kgsearch.googleapis.com/v1/entities:search';
$params = array(
  'query' => 'Taylor Swift',
  'limit' => 10,
  'indent' => TRUE,
  'key' => $api_key);
$url = $service_url . '?' . http_build_query($params);
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$response = json_decode(curl_exec($ch), true);
curl_close($ch);
foreach($response['itemListElement'] as $element) {
  echo $element['result']['name'] . '<br/>';
}

知識圖譜實體

知識圖譜包含數百萬個項目，用來描述使用者、地點及事物等實際實體。這些實體會構成圖表的節點。

知識圖譜中的實體類型如下：